IQ puzzles

[Nick12]

If anyone likes IQ puzzles I'll be posting one here every now and then. Here's a good one:

A man goes to a swimming pool and swims 50 lenghts of breaststroke. The pool measures 25m (82ft) long and 12m (39ft) wide. It is 1m (3ft) in the shallow end then after 15m (49ft) it shelves (at an angle of 45 degrees) to a depth of 2.5m (8ft). How much water is required to fill the pool?

Answer: to read the answer copy and paste the text to http://rot13.com/index.php

Abar. Vg zhfg nyernql or shyy vs n zna unf orra noyr gb fjvz va vg."

[Mikee]

What's that???

[Nick12]

An IQ puzzle is a lateral thinking puzzle. If that helps any.

[aquaMat]

Oh Nick.....

I hated that type of questions already in Math class in school...... and that was a lifetime back...

How am I supposed to solve that now, with so many brain cells lost along the way...??

[Mikee]

Nick wrote: An IQ puzzle is a lateral thinking puzzle. If that helps any.

Ahh, okay i know. I have this ever in the school in Math. Hehe, I love this NOT! That really sux...!!!

[ryos]

I read your answer, but I like mine better:

Gur cbby pbagnvaf sbhe uhaqerq fvkgl-fvk cbvag svir phovp zrgref bs jngre.

If anyone's curious how I got there, I'll post that as well.

[Freddy]

IQ ... who is in for this one?

I will prove that 1 = 2 .

Suppose:
a = 1
b = -2
a + b = c

Now:

a + b = c

(a + b) . (a + b) = c . (a + b)

a² + b² + 2ab = ac + bc

a2 + ab - ac = - ab -b² + bc

a . (a + b - c) = -b (a + b - c)

a = -b

1 = 2 8-)

[ryos]

Suppose:
a = 1
b = -2
a + b = c

Now:

a + b = c

(a + b) . (a + b) = c . (a + b)

a² + b² + 2ab = ac + bc

a2 + ab - ac = - ab -b² + bc

a . (a + b - c) = -b (a + b - c)

a = -b

At the risk of being a party pooper, let me debunk this one. It's easier to see with numbers, so let me just substitute in the numbers (up to line v, after which I change things a bit).

Suppose:
a = 1
b = -2
a + b = c = -1

Now:

i) 1 + -2 = -1

ii) (1 + -2)(1 + -2) = -1(1 + -2)

iii) 1² + (-2)² + 2(1)(-2) = 1(-1) + -2(-1)

iv) 1² + 1(-2) - 1(-1) = -1(-2) -(-2)² + -2(-1)

v) 1(1 + -2 - -1) = -(-2)(1 + -2 - -1)
Good for us; we've arrived at 0 = 0. Now, the next line is where it falls apart:

vi) [1(1 + -2 - -1)] / (1 + -2 - -1)  = [-(-2)(1 + -2 - -1)] / (1 + -2 - -1)

...which, if you cancel out the (1 + -2 - -1)'s, leads to the conclusion that 1 = 2. But dividing by (1 + -2 - -1) is an invalid operation, because (1 + -2 - -1) = 0.

Or, in other words, you're writing 0/0 = 0/0, which isn't anything because 0/0 is undefined. 8-)

[Mikee]

hehe okay wait...

37 a) (33:3)+(22:2)=

35 a) 1318,824:y=11,272

or as best example now in the school:

((44+55)x3) + (44,7x55,8) =

That's really nice, then that's very easy, but this y is a little harder but no hard to bring the result.

[Freddy]

Freddy wrote: a . (a + b - c) = -b (a + b - c)

a = -b

Simple: since a + b = c,
a + b - c = 0 and one is never allowed to devide with ZERO.

Because otherwise every X would be eaqual to any Y !